C-Program to convert Binary to Hexadecimal

Method I:

 

#include<stdio.h>

#include<string.h>

int main()

{

 int binaryNum[]={0,1,10,11,100,101,110,111,1000,1001,1010,1011,1100,1101,1110,1111},j=0,i;

 char hexa[20]="";

 unsigned long long int binary,number,temp;

 printf("Enter Binary number\n");

 scanf("%llu",&binary);

 temp=binary;

 while(temp!=0)

 {

  number=temp%10000;

  for(i=0;i<=15;i++)

  {

   if(binaryNum[i]==number)

   {

    if(i<=9)

    hexa[j]=(i+'0'); //i+'0' to convert integer to string

    else

    hexa[j]=(i+55);   

    j++;

   }

  }

  temp/=10000;

 }

 hexa[j]='\0';

 strrev(hexa);

 printf("Octal number for given Binary number %llu is %s\n",binary,hexa);

return 0;

}

Method II:

#include<stdio.h>

#include<string.h>

#include<math.h>

#include<ctype.h>

int ConvertFromBinarytoOther(unsigned long long int,int);

char *ConvertFromDecimalToHexa(int,int);

int main()

{

    char final[20];

    unsigned long long int binary,decimal;

    printf("Enter Binary Number\n");

    scanf("%llu",&binary);

    decimal=ConvertFromBinarytoOther(binary,2);//Converting binary to decimal

    strcpy(final,ConvertFromDecimalToHexa(decimal,16));//Converting Decimal to Hexa

    printf("HexaDecimal for given Binary %llu is %s\n",binary,final);

return(0);

}

char *ConvertFromDecimalToHexa(int decimal,int num)

{

 int temp,i,k=0;

 char final[20];

    temp=decimal;

    while(temp!=0)

    {

      i=temp%num;

      if(i>9)

      {

       final[k]=i+55;

       k++;

      }

      else{

       final[k]=(i+'0');//To convert from integer to character add (number+'0')

       k++;

      }

      temp=temp/num;

     }

     final[k]='\0';

     return(strrev(final));

}

int ConvertFromBinarytoOther(unsigned long long int binary,int num)

{

 int i,inc=0,final=0;

 unsigned long long int temp;

    temp=binary;

    while(temp!=0)

    {

      i=temp%10;

      final=final+(i*pow(num,inc));

      temp=temp/10;

      inc++;

     }

     return(final);

 }

C-Program to Covert Binary to Octal

#include<stdio.h>

int main()

{

 int octalNum[]={0,1,10,11,100,101,110,111};

 long int binary,i,number,temp,octal=0,j=1;

 printf("Enter Binary number\n");

 scanf("%ld",&binary);

 temp=binary;

 while(temp!=0)

 {

  number=temp%1000;

  for(i=0;i<=7;i++)

  {

   if(octalNum[i]==number)

   {

    octal=octal+(i*j);

   }

  }

  j*=10;

  temp/=1000;

 }

 printf("Octal number for given Binary number %ld is %ld\n",binary,octal);

return 0;

}

Method II:

#include<stdio.h>

#include<math.h>

int ConvertFromBinarytoOther(int);

int ConvertFromDecimalToOther(int);

int main()

{

 int final,num,binary,decimal;

 printf("Enter Binary Number\n");

 scanf("%d",&binary);

 decimal=ConvertFromBinarytoOther(binary);//Converting binary to decimal

 final=ConvertFromDecimalToOther(decimal);//Converting decimal to octal

 //So binary to Octal

 printf("Octal number of Binary number %d is %d\n",binary,final);

return(0);

}

int ConvertFromDecimalToOther(int decimal)

{

 int temp,i,j=1,final=0;

    temp=decimal;

    while(temp!=0)

    {

      i=temp%8;

      final=final+(i*j);

      temp=temp/8;

      j=j*10;

     }

     return(final);

}

int ConvertFromBinarytoOther(int binary)

{

 int final=0,i,inc=0,temp;

    temp=binary;

    while(temp!=0)

    {

      i=temp%10;

      final=final+(i*pow(2,inc));

      temp=temp/10;

      inc++;

     }

     return(final);

}