C-Program to Find Words with Consecutive Vowels in Sentence

#include<stdio.h>

#include<string.h>

#include<ctype.h>

int GetVowelOrNot(char c,char c1);

int main()

{

 int i,j,k=0,flag=0,checkVowel,len,count=0;

 char str[100],substr[30],mainstr[30][20];

 printf("Enter a string to find words with consecutive vowels\n");

 gets(str);

 len=strlen(str);

 printf("Words with Consecutive Vowels\n");

 for(i=0;i<=len;i++)//i<=len for checking last word also because there will be no space at the end of sentence

 {

  if(str[i]!=' ' && i!=len)

  {

   substr[k++]=str[i];

  }

  else

  {

   substr[k]='\0';

   int sublen=strlen(substr);

   for(j=0;j<sublen-1;j++)

   {

       checkVowel=GetVowelOrNot(tolower(substr[j]),tolower(substr[j+1]));

    if(checkVowel==1)

    {

     flag=1;

     strcpy(mainstr[count],substr);

     count++;

        break;

    }

   }

   k=0;

  }

 }

 //To remove repeated words

 len=count;

   for(i=0;i<len;i++)

    {

      for(j=i+1;j<len;)

       {

         if(strcmp(mainstr[i],mainstr[j])==0)

          {    

             for(k=j;k<len;k++)

              {

                strcpy(mainstr[k],mainstr[k+1]);

              }

                len--;

           }

          else

           {

             j++;

           }

        }

     }

   if(flag!=1)

   {

    printf("are not there\n");

   }

   else

   {

     for(i=0;i<len;i++)

     printf("%s\n",mainstr[i]);

   } 

return 0;

}

int GetVowelOrNot(char c,char c1)

{

 int x=0,y=0;

   if(c=='a' || c=='e'||c=='i'||c=='o'||c=='u')

   {

      x=1;

   }

   if(c1=='a' || c1=='e'||c1=='i'||c1=='o'||c1=='u')

   {

      y=1;

   }

    if(x==1 && y==1)

    return 1;

    else

    return 0;

}